Combinatorics Calculator (Permutations & Combinations)

Calculate permutations, variations, and combinations (with and without repetition) with clear step-by-step derivations. Features an interactive decision tree, urn model visualizer, and practice trainer.

WhatsAppTelegram

⚙️Kombinatorisches Modell auswählen

Wähle zwischen Permutation, Variation oder Kombination mit/ohne Wiederholung.

Beispiele:
Anzahl aller verfügbaren Elemente
Anzahl der ausgewählten Elemente
🎲Interaktive Modell- & Entscheidungsbaum-Visualisierung
1Elemente-Umfang

Werden alle n Elemente angeordnet?

➔ Nein, Auswahl von k Elementen
2Reihenfolge

Spielt die Ziehungsreihenfolge eine Rolle?

➔ Nein (Ungeordnet / Kombination)
3Wiederholung / Zurücklegen

Dürfen Elemente mehrfach vorkommen?

➔ Nein (ohne Wiederholung)
Erkanntes Modell:
Kombination ohne Wiederholung (Ungeordnet, ohne Zurücklegen)

Mit einem Griff werden k Kugeln gleichzeitig aus der Urne mit n Kugeln gezogen. Die Reihenfolge ist egal.

Praxisbeispiel: Lotto 6 aus 49 (Ziehung von 6 Gewinnzahlen aus 49) oder Bildung eines 3er-Ausschusses aus n Mitgliedern.
Berechnete Anzahl der Möglichkeiten:
13.983.816
(496)=49!6!⋅(49−6)!=13.983.816\binom{49}{6} = \frac{49!}{6! \cdot (49-6)!} = \mathbf{13.983.816}

📝Ausführlicher Rechenweg & mathematische Begründung

Schritt 1: Binomialkoeffizient anwenden

Da die Ziehungsreihenfolge irrelevant ist, teilt man die Variation durch $k!$:

(nk)=n⋅(n−1)…(n−k+1)k⋅(k−1)…1\binom{n}{k} = \frac{n \cdot (n-1) \dots (n-k+1)}{k \cdot (k-1) \dots 1}
Schritt 2: Werte einsetzen und kürzen

Kombinationen für $n = 49$ und $k = 6$:

(496)=49⋅48⋅47⋅46⋅45⋅446⋅5⋅4⋅3⋅2⋅1=13.983.816\binom{49}{6} = \frac{49 \cdot 48 \cdot 47 \cdot 46 \cdot 45 \cdot 44}{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1} = \mathbf{13.983.816}

Historical Origin & The Challenge Solved

Why was this mathematics developed, where does it come from, and what real-world problem did it solve?

📜
Epoche & Zeitalter17th Century & Baroque (1666 – 1700)
Pioniere: Gottfried Wilhelm Leibniz, Blaise Pascal, Jacob Bernoulli

1. Cryptography, Secret Ciphers & Combination Locks

Diplomats and military commanders encrypted state secrets via letter substitutions. To crack codes or forge unpickable combination locks, one had to compute exactly how many permutations and combinations existed.

2. De Arte Combinatoria & Factorials

At age 20, Leibniz published "Dissertatio de Arte Combinatoria" (1666). He formalized factorials (n!), permutations, variations, and combinations into a systematic discipline of logical counting.

3. Cybersecurity, Genomics & Network Routing

Password entropy calculations against brute-force attacks, genomic DNA sequencing permutations, and logistics routing algorithms rely on combinatorics.

„Combinatorics is the art of unfolding the entire universe of possibilities from a few fundamental elements.“ — Gottfried Wilhelm Leibniz

Praxisnutzen & Reale Anwendungsfälle

Warum lernen wir das? So wird diese Mathematik in Wirtschaft, Technik, Wissenschaft und Alltag praktisch angewendet:

Cybersecurity & Cryptography

Password Entropy & Brute Force

Security analysts calculate keyspaces to assess cryptographic strength against brute-force attacks.

Praxis-Beispiel:

An 8-character password from 62 alphanumeric characters has 62^8 ≈ 2.18 · 10^14 combinations.

Gaming & Probability

Lotteries & Card Games (Poker)

Calculating exact win probabilities by taking favorable outcomes over total possible combinations.

Praxis-Beispiel:

In 5-card poker, there are (52 choose 5) = 2,598,960 possible hands from a standard deck.

Genetics & Bioinformatics

DNA Codons & Amino Acids

Counting sequence configurations for genetic coding across base pairs A, C, G, and T.

Praxis-Beispiel:

A 3-base codon yields 4^3 = 64 possible combinations encoding 20 amino acids.

Mathematical Foundations: Combinatorics & Urn Models

Combinatorics deals with counting the number of possible arrangements (permutations) or selections (variations and combinations) of k elements from a set of n elements. Choosing the right formula depends on whether order matters and whether repetition is allowed.

For ordered arrangements, we distinguish permutations without repetition (P_n = n!), variations without repetition (V = n! / (n-k)!), and variations with repetition (V = n^k, e.g. PIN codes or combination locks).

For unordered selections, we use combinations. Combination without repetition is the binomial coefficient (n choose k) = n! / (k!(n-k)!), famous from lottery draws. Combination with repetition is calculated via (n+k-1 choose k).

Frequently Asked Questions (FAQ) about Combinatorics

What is the difference between combination and permutation/variation?

In permutations and variations, the order of elements matters (e.g. 1st, 2nd, 3rd place). In combinations, the order does not matter (e.g. lottery numbers or a team selection).

When do I use factorial n!?

Factorial n! is used when arranging all n distinct items in a complete sequence without repetition.

How does the combinatorics decision tree work?

It guides you through three questions: 1. Are all elements used? 2. Does order matter? 3. Is replacement/repetition allowed?