Binomial Distribution Calculator & Bernoulli Histogram

Calculate exact and cumulative binomial probabilities B(n; p) with step-by-step solutions. Features interactive histogram plotting, Gaussian normal curve overlay, sigma intervals, and trainer.

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⚙️Verteilungsparameter n und p festlegen

Passe Versuchszahl n und Trefferwahrscheinlichkeit p flexibel an.

Beispiele:
📊Wahrscheinlichkeits-Histogramm B(n=20; p=0.50)
0.0%5.1%10.1%15.2%20.3%4%7%12%16%18%16%12%7%4%μ = 10.0002468101214161820Trefferanzahl k
Ausgewählte Treffer (EXACT)
Gauß-Glockenkurve
Erwartungswert μ = 10.00
σ = 2.24 (σ ≤ 3)
Erwartungswert μ
10,00
μ = n · p
Standardabw. σ
2,236
σ = √(n · p · q)
Varianz σ²
5,000
Var(X) = n · p · (1-p)
1σ-Intervall (≈68,3%)
[8 ; 12]
[μ - σ ; μ + σ]
Berechnete Wahrscheinlichkeit:
17,6197 %
Dezimalwert: 0,176197

📝Ausführlicher Rechenweg & Formelherleitung

Schritt 1: Kenngrößen der Binomialverteilung B(n; p)

Bei $n = 20$ Versuchen und Trefferwahrscheinlichkeit $p = 0,50$ ($q = 1 - p = 0,50$):

μ=n⋅p=20⋅0,50=10,00,σ=n⋅p⋅(1−p)=5,000=2,236\mu = n \cdot p = 20 \cdot 0,50 = \mathbf{10,00}, \quad \sigma = \sqrt{n \cdot p \cdot (1-p)} = \sqrt{5,000} = \mathbf{2,236}
Schritt 2: Bernoulli-Formel für exakt k Treffer

Die Formel für genau $k$ Treffer lautet $P(X = k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k}$:

P(X=10)=(2010)⋅(0,50)10⋅(0,50)10=0,176197  (≈17.62%)P(X = 10) = \binom{20}{10} \cdot (0,50)^{10} \cdot (0,50)^{10} = \mathbf{0,176197} \; (\approx 17.62\%)
Schritt 3: Sigma-Umgebungen & Laplace-Bedingung

Da $\sigma = 2,24 \le 3$, ist die Verteilung zu schmal für eine stetige Glockenkurven-Approximation.

[μ−σ,μ+σ]=[8,12](≈68,3%),[μ−2σ,μ+2σ]=[6,14](≈95,4%)[\mu - \sigma, \mu + \sigma] = [8, 12] \quad (\approx 68{,}3\%), \quad [\mu - 2\sigma, \mu + 2\sigma] = [6, 14] \quad (\approx 95{,}4\%)

Historical Origin & The Challenge Solved

Why was this mathematics developed, where does it come from, and what real-world problem did it solve?

📜
Epoche & ZeitalterEarly 18th Century (1713)
Pioniere: Jacob Bernoulli ("Ars Conjectandi")

1. Quality Control in Coin Minting & Gambler Runs

Royal mints needed to ensure minted gold coins met strict purity tolerances. Authorities had no mathematical model to calculate the probability of finding exactly k defective coins in a batch of 100 samples.

2. Bernoulli Trials & The Binomial Probability Formula

In "Ars Conjectandi", Bernoulli proved the formula P(X=k) = (n choose k) * p^k * (1-p)^(n-k) and established the Law of Large Numbers: observed frequencies converge to theoretical probabilities over large samples.

3. Industrial Quality Assurance, Polling & A/B Testing

Website A/B testing, semiconductor chip manufacturing yield metrics, and national election exit polls rely directly on the binomial distribution.

„Even the most foolish person instinctively perceives that more observations confer greater certainty.“ — Jacob Bernoulli

Praxisnutzen & Reale Anwendungsfälle

Warum lernen wir das? So wird diese Mathematik in Wirtschaft, Technik, Wissenschaft und Alltag praktisch angewendet:

Quality Control & Manufacturing

Lot Inspection & Defect Rates

Manufacturers verify defect rates and acceptance thresholds using random sample batches.

Praxis-Beispiel:

Testing 100 components with 2% defect rate for at most 3 failures.

Polling & Market Research

Voter Surveys & Confidence Intervals

Statisticians calculate margins of error for political approval ratings.

Praxis-Beispiel:

Estimating voting proportions from a sample of 1,000 citizens with 95% confidence.

Medical Science

Clinical Drug Trials

Evaluating recovery rates and treatment efficacy in randomized patient groups.

Praxis-Beispiel:

Probability of a new therapy curing at least 80 out of 100 patients.

Mathematical Foundations: Binomial Distribution & Bernoulli Trials

A Bernoulli trial is a random experiment with exactly two outcomes (success with probability p, failure with probability q = 1 - p). Repeating this trial n times independently forms a Bernoulli chain of length n.

The random variable X denotes the number of successes. The probability of exactly k successes is given by the Bernoulli formula: P(X = k) = (n choose k) · p^k · (1-p)^(n-k).

Key metrics are expected value μ = n · p, variance Var(X) = n · p · (1-p), and standard deviation σ = √(n · p · (1-p)). If σ > 3 (Laplace condition), the distribution can be approximated by a continuous Gaussian normal distribution.

Frequently Asked Questions (FAQ) about Binomial Distribution

When is a process binomially distributed?

When each trial has only 2 outcomes, the success probability p remains constant (drawing with replacement), and all trials are independent.

How do you calculate at least k successes P(X ≥ k)?

Using the complement rule: P(X ≥ k) = 1 - P(X ≤ k-1). For at least 1 success, use P(X ≥ 1) = 1 - (1-p)^n.

What are the sigma intervals?

They denote symmetric ranges around μ: The 1σ interval contains ≈68.3% of the distribution, 2σ contains ≈95.4%, and 3σ contains ≈99.7%.